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134426644250333 is a prime number
BaseRepresentation
bin11110100100001010100100…
…011000001111111011011101
3122121222001122222010111221012
4132210022210120033323131
5120104421231412002313
61153522425310545005
740213001363050001
oct3644124430177335
9577861588114835
10134426644250333
1139918024202896
12130b094b208165
135a014bba82546
14252a3da17a701
151081b2b15eda8
hex7a42a460fedd

134426644250333 has 2 divisors, whose sum is σ = 134426644250334. Its totient is φ = 134426644250332.

The previous prime is 134426644250237. The next prime is 134426644250401. The reversal of 134426644250333 is 333052446624431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134425543205209 + 1101045124 = 11594203^2 + 33182^2 .

It is a cyclic number.

It is not a de Polignac number, because 134426644250333 - 210 = 134426644249309 is a prime.

It is a super-2 number, since 2×1344266442503332 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134426644250033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67213322125166 + 67213322125167.

It is an arithmetic number, because the mean of its divisors is an integer number (67213322125167).

Almost surely, 2134426644250333 is an apocalyptic number.

It is an amenable number.

134426644250333 is a deficient number, since it is larger than the sum of its proper divisors (1).

134426644250333 is an equidigital number, since it uses as much as digits as its factorization.

134426644250333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14929920, while the sum is 50.

The spelling of 134426644250333 in words is "one hundred thirty-four trillion, four hundred twenty-six billion, six hundred forty-four million, two hundred fifty thousand, three hundred thirty-three".