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134428289927471 is a prime number
BaseRepresentation
bin11110100100001100000110…
…011110000000100100101111
3122121222012220122202120120022
4132210030012132000210233
5120104433114210134341
61153523300455312355
740213060225061351
oct3644140636004457
9577865818676508
10134428289927471
1139918799142441
12130b112a37b6bb
135a016c19bbbb7
14252a5149610d1
151081bc5882e4b
hex7a430678092f

134428289927471 has 2 divisors, whose sum is σ = 134428289927472. Its totient is φ = 134428289927470.

The previous prime is 134428289927443. The next prime is 134428289927497. The reversal of 134428289927471 is 174729982824431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134428289927471 - 222 = 134428285733167 is a prime.

It is a super-3 number, since 3×1344282899274713 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 134428289927395 and 134428289927404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134428289923471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67214144963735 + 67214144963736.

It is an arithmetic number, because the mean of its divisors is an integer number (67214144963736).

Almost surely, 2134428289927471 is an apocalyptic number.

134428289927471 is a deficient number, since it is larger than the sum of its proper divisors (1).

134428289927471 is an equidigital number, since it uses as much as digits as its factorization.

134428289927471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 390168576, while the sum is 71.

The spelling of 134428289927471 in words is "one hundred thirty-four trillion, four hundred twenty-eight billion, two hundred eighty-nine million, nine hundred twenty-seven thousand, four hundred seventy-one".