Base | Representation |
---|---|
bin | 1100001110100000010001… |
… | …1100001101010100100101 |
3 | 1202121011120020022122000211 |
4 | 3003220010130031110211 |
5 | 3230223410431434231 |
6 | 44331435452335421 |
7 | 2555151024536401 |
oct | 303500434152445 |
9 | 52534506278024 |
10 | 13443322139941 |
11 | 431330a977031 |
12 | 16114a5474571 |
13 | 766913710795 |
14 | 346935a96101 |
15 | 184a5953eeb1 |
hex | c3a0470d525 |
13443322139941 has 2 divisors, whose sum is σ = 13443322139942. Its totient is φ = 13443322139940.
The previous prime is 13443322139903. The next prime is 13443322139983. The reversal of 13443322139941 is 14993122334431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8499498852100 + 4943823287841 = 2915390^2 + 2223471^2 .
It is a cyclic number.
It is not a de Polignac number, because 13443322139941 - 27 = 13443322139813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13443322139441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721661069970 + 6721661069971.
It is an arithmetic number, because the mean of its divisors is an integer number (6721661069971).
Almost surely, 213443322139941 is an apocalyptic number.
It is an amenable number.
13443322139941 is a deficient number, since it is larger than the sum of its proper divisors (1).
13443322139941 is an equidigital number, since it uses as much as digits as its factorization.
13443322139941 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1679616, while the sum is 49.
The spelling of 13443322139941 in words is "thirteen trillion, four hundred forty-three billion, three hundred twenty-two million, one hundred thirty-nine thousand, nine hundred forty-one".
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