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13443322139941 is a prime number
BaseRepresentation
bin1100001110100000010001…
…1100001101010100100101
31202121011120020022122000211
43003220010130031110211
53230223410431434231
644331435452335421
72555151024536401
oct303500434152445
952534506278024
1013443322139941
11431330a977031
1216114a5474571
13766913710795
14346935a96101
15184a5953eeb1
hexc3a0470d525

13443322139941 has 2 divisors, whose sum is σ = 13443322139942. Its totient is φ = 13443322139940.

The previous prime is 13443322139903. The next prime is 13443322139983. The reversal of 13443322139941 is 14993122334431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8499498852100 + 4943823287841 = 2915390^2 + 2223471^2 .

It is a cyclic number.

It is not a de Polignac number, because 13443322139941 - 27 = 13443322139813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13443322139441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721661069970 + 6721661069971.

It is an arithmetic number, because the mean of its divisors is an integer number (6721661069971).

Almost surely, 213443322139941 is an apocalyptic number.

It is an amenable number.

13443322139941 is a deficient number, since it is larger than the sum of its proper divisors (1).

13443322139941 is an equidigital number, since it uses as much as digits as its factorization.

13443322139941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1679616, while the sum is 49.

The spelling of 13443322139941 in words is "thirteen trillion, four hundred forty-three billion, three hundred twenty-two million, one hundred thirty-nine thousand, nine hundred forty-one".