Base | Representation |
---|---|
bin | 1100001110100000010001… |
… | …1100001101010101100100 |
3 | 1202121011120020022122010011 |
4 | 3003220010130031111210 |
5 | 3230223410431440004 |
6 | 44331435452340004 |
7 | 2555151024536521 |
oct | 303500434152544 |
9 | 52534506278104 |
10 | 13443322140004 |
11 | 431330a977089 |
12 | 16114a5474604 |
13 | 766913710813 |
14 | 346935a96148 |
15 | 184a59540004 |
hex | c3a0470d564 |
13443322140004 has 48 divisors (see below), whose sum is σ = 24074953854336. Its totient is φ = 6566422579200.
The previous prime is 13443322139983. The next prime is 13443322140067. The reversal of 13443322140004 is 40004122334431.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20924484 + ... + 21557380.
It is an arithmetic number, because the mean of its divisors is an integer number (501561538632).
Almost surely, 213443322140004 is an apocalyptic number.
It is an amenable number.
13443322140004 is a deficient number, since it is larger than the sum of its proper divisors (10631631714332).
13443322140004 is a wasteful number, since it uses less digits than its factorization.
13443322140004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 633556 (or 633554 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 13443322140004 its reverse (40004122334431), we get a palindrome (53447444474435).
The spelling of 13443322140004 in words is "thirteen trillion, four hundred forty-three billion, three hundred twenty-two million, one hundred forty thousand, four".
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