Base | Representation |
---|---|
bin | 111110100110011011… |
… | …0001101101101110111 |
3 | 110211222212220112001021 |
4 | 1331030312031231313 |
5 | 4200304404012201 |
6 | 141431403242011 |
7 | 12466244624503 |
oct | 1751466155567 |
9 | 424885815037 |
10 | 134433266551 |
11 | 5201608a991 |
12 | 22079519307 |
13 | c8a54b458c |
14 | 67141a3303 |
15 | 376c16dea1 |
hex | 1f4cd8db77 |
134433266551 has 2 divisors, whose sum is σ = 134433266552. Its totient is φ = 134433266550.
The previous prime is 134433266543. The next prime is 134433266557. The reversal of 134433266551 is 155662334431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134433266551 - 23 = 134433266543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134433266498 and 134433266507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134433266557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67216633275 + 67216633276.
It is an arithmetic number, because the mean of its divisors is an integer number (67216633276).
Almost surely, 2134433266551 is an apocalyptic number.
134433266551 is a deficient number, since it is larger than the sum of its proper divisors (1).
134433266551 is an equidigital number, since it uses as much as digits as its factorization.
134433266551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 777600, while the sum is 43.
The spelling of 134433266551 in words is "one hundred thirty-four billion, four hundred thirty-three million, two hundred sixty-six thousand, five hundred fifty-one".
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