Base | Representation |
---|---|
bin | 1100001110100000010100… |
… | …0010011000000100010111 |
3 | 1202121011120221010221222112 |
4 | 3003220011002120010113 |
5 | 3230223421012123211 |
6 | 44331440451021235 |
7 | 2555151205561046 |
oct | 303500502300427 |
9 | 52534527127875 |
10 | 13443332145431 |
11 | 4313315590331 |
12 | 16114a889a81b |
13 | 7669158049a6 |
14 | 34693713c55d |
15 | 184a5a36988b |
hex | c3a05098117 |
13443332145431 has 2 divisors, whose sum is σ = 13443332145432. Its totient is φ = 13443332145430.
The previous prime is 13443332145409. The next prime is 13443332145533. The reversal of 13443332145431 is 13454123334431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13443332145431 - 218 = 13443331883287 is a prime.
It is a super-2 number, since 2×134433321454312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13443332345431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721666072715 + 6721666072716.
It is an arithmetic number, because the mean of its divisors is an integer number (6721666072716).
Almost surely, 213443332145431 is an apocalyptic number.
13443332145431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13443332145431 is an equidigital number, since it uses as much as digits as its factorization.
13443332145431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 622080, while the sum is 41.
Adding to 13443332145431 its reverse (13454123334431), we get a palindrome (26897455479862).
The spelling of 13443332145431 in words is "thirteen trillion, four hundred forty-three billion, three hundred thirty-two million, one hundred forty-five thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •