Base | Representation |
---|---|
bin | 1100001110100000011001… |
… | …1011001010011001110101 |
3 | 1202121011122112221110001212 |
4 | 3003220012123022121311 |
5 | 3230223442441422102 |
6 | 44331443041531205 |
7 | 2555151610446536 |
oct | 303500633123165 |
9 | 52534575843055 |
10 | 13443355420277 |
11 | 4313327738042 |
12 | 16114b4643b05 |
13 | 76691a5938a3 |
14 | 34693a27a68d |
15 | 184a5c415c52 |
hex | c3a066ca675 |
13443355420277 has 2 divisors, whose sum is σ = 13443355420278. Its totient is φ = 13443355420276.
The previous prime is 13443355420193. The next prime is 13443355420283. The reversal of 13443355420277 is 77202455334431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7551113789041 + 5892241631236 = 2747929^2 + 2427394^2 .
It is a cyclic number.
It is not a de Polignac number, because 13443355420277 - 28 = 13443355420021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13443355450277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721677710138 + 6721677710139.
It is an arithmetic number, because the mean of its divisors is an integer number (6721677710139).
Almost surely, 213443355420277 is an apocalyptic number.
It is an amenable number.
13443355420277 is a deficient number, since it is larger than the sum of its proper divisors (1).
13443355420277 is an equidigital number, since it uses as much as digits as its factorization.
13443355420277 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8467200, while the sum is 50.
The spelling of 13443355420277 in words is "thirteen trillion, four hundred forty-three billion, three hundred fifty-five million, four hundred twenty thousand, two hundred seventy-seven".
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