Base | Representation |
---|---|
bin | 1100001110100000011001… |
… | …1011001010111001101111 |
3 | 1202121011122112221112212111 |
4 | 3003220012123022321233 |
5 | 3230223442442003234 |
6 | 44331443041544451 |
7 | 2555151610455514 |
oct | 303500633127157 |
9 | 52534575845774 |
10 | 13443355422319 |
11 | 4313327739629 |
12 | 16114b4645127 |
13 | 76691a5947b4 |
14 | 34693a27b30b |
15 | 184a5c416664 |
hex | c3a066cae6f |
13443355422319 has 2 divisors, whose sum is σ = 13443355422320. Its totient is φ = 13443355422318.
The previous prime is 13443355422269. The next prime is 13443355422347. The reversal of 13443355422319 is 91322455334431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13443355422319 - 221 = 13443353325167 is a prime.
It is a super-2 number, since 2×134433554223192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13443355425319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721677711159 + 6721677711160.
It is an arithmetic number, because the mean of its divisors is an integer number (6721677711160).
Almost surely, 213443355422319 is an apocalyptic number.
13443355422319 is a deficient number, since it is larger than the sum of its proper divisors (1).
13443355422319 is an equidigital number, since it uses as much as digits as its factorization.
13443355422319 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4665600, while the sum is 49.
The spelling of 13443355422319 in words is "thirteen trillion, four hundred forty-three billion, three hundred fifty-five million, four hundred twenty-two thousand, three hundred nineteen".
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