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13443401232 = 243293356953
BaseRepresentation
bin11001000010100101…
…00000011000010000
31021200220010112121100
430201102200120100
5210013002314412
610101550424400
7654066011412
oct144122403020
937626115540
1013443401232
1157794a4358
122732202100
1313631cacb1
149175ca9b2
1553a339edc
hex3214a0610

13443401232 has 30 divisors (see below), whose sum is σ = 37622852462. Its totient is φ = 4481133696.

The previous prime is 13443401203. The next prime is 13443401243. The reversal of 13443401232 is 23210434431.

It can be written as a sum of positive squares in only one way, i.e., 9501570576 + 3941830656 = 97476^2 + 62784^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13443401196 and 13443401205.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 46678333 + ... + 46678620.

Almost surely, 213443401232 is an apocalyptic number.

13443401232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13443401232 is an abundant number, since it is smaller than the sum of its proper divisors (24179451230).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13443401232 is a wasteful number, since it uses less digits than its factorization.

13443401232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93356967 (or 93356958 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 13443401232 its reverse (23210434431), we get a palindrome (36653835663).

The spelling of 13443401232 in words is "thirteen billion, four hundred forty-three million, four hundred one thousand, two hundred thirty-two".

Divisors: 1 2 3 4 6 8 9 12 16 18 24 36 48 72 144 93356953 186713906 280070859 373427812 560141718 746855624 840212577 1120283436 1493711248 1680425154 2240566872 3360850308 4481133744 6721700616 13443401232