Base | Representation |
---|---|
bin | 11110100100010001011011… |
… | …100011111010000110000010 |
3 | 122121222202200110210121101211 |
4 | 132210101123203322012002 |
5 | 120110031324200120300 |
6 | 1153530044402120334 |
7 | 40213352103141301 |
oct | 3644213343720602 |
9 | 577882613717354 |
10 | 134434012504450 |
11 | 3992016540a1aa |
12 | 130b22669500aa |
13 | 5a020c4463219 |
14 | 252a8d8996438 |
15 | 1081e0ce6b4ba |
hex | 7a445b8fa182 |
134434012504450 has 12 divisors (see below), whose sum is σ = 250047263258370. Its totient is φ = 53773605001760.
The previous prime is 134434012504339. The next prime is 134434012504501. The reversal of 134434012504450 is 54405210434431.
It can be written as a sum of positive squares in 3 ways, for example, as 131678356064161 + 2755656440289 = 11475119^2 + 1660017^2 .
It is a super-2 number, since 2×1344340125044502 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1344340124995 + ... + 1344340125094.
Almost surely, 2134434012504450 is an apocalyptic number.
134434012504450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
134434012504450 is a deficient number, since it is larger than the sum of its proper divisors (115613250753920).
134434012504450 is a wasteful number, since it uses less digits than its factorization.
134434012504450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2688680250101 (or 2688680250096 counting only the distinct ones).
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 134434012504450 its reverse (54405210434431), we get a palindrome (188839222938881).
The spelling of 134434012504450 in words is "one hundred thirty-four trillion, four hundred thirty-four billion, twelve million, five hundred four thousand, four hundred fifty".
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