1344400400131 has 2 divisors, whose sum is σ = 1344400400132. Its totient is φ = 1344400400130.

The previous prime is 1344400400111. The next prime is 1344400400137. The reversal of 1344400400131 is 1310040044431.

It is a strong prime.

It is an emirp because it is prime and its reverse (1310040044431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1344400400131 - 2³⁵ = 1310040661763 is a prime.

It is a super-2 number, since 2×1344400400131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1344400400096 and 1344400400105.

It is not a weakly prime, because it can be changed into another prime (1344400400137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672200200065 + 672200200066.

It is an arithmetic number, because the mean of its divisors is an integer number (672200200066).

Almost surely, 2^{1344400400131} is an apocalyptic number.

1344400400131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344400400131 is an equidigital number, since it uses as much as digits as its factorization.

1344400400131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1344400400131 its reverse (1310040044431), we get a palindrome (2654440444562).

The spelling of 1344400400131 in words is "one trillion, three hundred forty-four billion, four hundred million, four hundred thousand, one hundred thirty-one".