Base | Representation |
---|---|
bin | 1100001110100011101010… |
… | …0101101101101010101111 |
3 | 1202121020220112202020212012 |
4 | 3003220322211231222233 |
5 | 3230232241013221031 |
6 | 44332105544031435 |
7 | 2555212365406142 |
oct | 303507245555257 |
9 | 52536815666765 |
10 | 13444230601391 |
11 | 4313736758617 |
12 | 16116b976257b |
13 | 766a299aa635 |
14 | 3469c05b6059 |
15 | 184aae18db2b |
hex | c3a3a96daaf |
13444230601391 has 2 divisors, whose sum is σ = 13444230601392. Its totient is φ = 13444230601390.
The previous prime is 13444230601387. The next prime is 13444230601429. The reversal of 13444230601391 is 19310603244431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13444230601391 - 22 = 13444230601387 is a prime.
It is a super-2 number, since 2×134442306013912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13444230601591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722115300695 + 6722115300696.
It is an arithmetic number, because the mean of its divisors is an integer number (6722115300696).
Almost surely, 213444230601391 is an apocalyptic number.
13444230601391 is a deficient number, since it is larger than the sum of its proper divisors (1).
13444230601391 is an equidigital number, since it uses as much as digits as its factorization.
13444230601391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 41.
The spelling of 13444230601391 in words is "thirteen trillion, four hundred forty-four billion, two hundred thirty million, six hundred one thousand, three hundred ninety-one".
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