Base | Representation |
---|---|
bin | 11110100100011001001010… |
… | …110011111010111110011011 |
3 | 122122000120010112111110122102 |
4 | 132210121022303322332123 |
5 | 120110200333241034113 |
6 | 1153533541055114015 |
7 | 40214065024611335 |
oct | 3644311263727633 |
9 | 578016115443572 |
10 | 134442321424283 |
11 | 399237395a36a4 |
12 | 130b39a551290b |
13 | 5a02b199a8132 |
14 | 252b0862b6455 |
15 | 1082247638758 |
hex | 7a464acfaf9b |
134442321424283 has 2 divisors, whose sum is σ = 134442321424284. Its totient is φ = 134442321424282.
The previous prime is 134442321424273. The next prime is 134442321424303. The reversal of 134442321424283 is 382424123244431.
It is a weak prime.
It is an emirp because it is prime and its reverse (382424123244431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134442321424283 - 214 = 134442321407899 is a prime.
It is not a weakly prime, because it can be changed into another prime (134442321424273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67221160712141 + 67221160712142.
It is an arithmetic number, because the mean of its divisors is an integer number (67221160712142).
Almost surely, 2134442321424283 is an apocalyptic number.
134442321424283 is a deficient number, since it is larger than the sum of its proper divisors (1).
134442321424283 is an equidigital number, since it uses as much as digits as its factorization.
134442321424283 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3538944, while the sum is 47.
The spelling of 134442321424283 in words is "one hundred thirty-four trillion, four hundred forty-two billion, three hundred twenty-one million, four hundred twenty-four thousand, two hundred eighty-three".
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