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134442321424399 is a prime number
BaseRepresentation
bin11110100100011001001010…
…110011111011000000001111
3122122000120010112111110210201
4132210121022303323000033
5120110200333241040044
61153533541055114331
740214065024611562
oct3644311263730017
9578016115443721
10134442321424399
11399237395a379a
12130b39a55129a7
135a02b199a81c1
14252b0862b64d9
1510822476387d4
hex7a464acfb00f

134442321424399 has 2 divisors, whose sum is σ = 134442321424400. Its totient is φ = 134442321424398.

The previous prime is 134442321424351. The next prime is 134442321424421. The reversal of 134442321424399 is 993424123244431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134442321424399 - 211 = 134442321422351 is a prime.

It is a super-2 number, since 2×1344423214243992 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134442321424339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67221160712199 + 67221160712200.

It is an arithmetic number, because the mean of its divisors is an integer number (67221160712200).

Almost surely, 2134442321424399 is an apocalyptic number.

134442321424399 is a deficient number, since it is larger than the sum of its proper divisors (1).

134442321424399 is an equidigital number, since it uses as much as digits as its factorization.

134442321424399 is an evil number, because the sum of its binary digits is even.

The product of its digits is 17915904, while the sum is 55.

The spelling of 134442321424399 in words is "one hundred thirty-four trillion, four hundred forty-two billion, three hundred twenty-one million, four hundred twenty-four thousand, three hundred ninety-nine".