Base | Representation |
---|---|
bin | 10011100100000101111… |
… | …110110000100000011111 |
3 | 11202112012022000102120222 |
4 | 103210011332300200133 |
5 | 134011340311220333 |
6 | 2505341555431555 |
7 | 166063051544312 |
oct | 23440576604037 |
9 | 4675168012528 |
10 | 1344425101343 |
11 | 479192a14385 |
12 | 1986852b55bb |
13 | 99a17b8b05c |
14 | 490db726979 |
15 | 24e89153298 |
hex | 13905fb081f |
1344425101343 has 2 divisors, whose sum is σ = 1344425101344. Its totient is φ = 1344425101342.
The previous prime is 1344425101339. The next prime is 1344425101399. The reversal of 1344425101343 is 3431015244431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1344425101343 - 22 = 1344425101339 is a prime.
It is a super-2 number, since 2×13444251013432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344425109343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672212550671 + 672212550672.
It is an arithmetic number, because the mean of its divisors is an integer number (672212550672).
Almost surely, 21344425101343 is an apocalyptic number.
1344425101343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344425101343 is an equidigital number, since it uses as much as digits as its factorization.
1344425101343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 35.
The spelling of 1344425101343 in words is "one trillion, three hundred forty-four billion, four hundred twenty-five million, one hundred one thousand, three hundred forty-three".
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