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134443410131 is a prime number
BaseRepresentation
bin111110100110101110…
…0111010001011010011
3110212000120222212102102
41331031130322023103
54200320003111011
6141432404511015
712466430062562
oct1751534721323
9425016885372
10134443410131
1152020888a08
12220809ab46b
13c8a76265b4
146715683bd9
15376cec473b
hex1f4d73a2d3

134443410131 has 2 divisors, whose sum is σ = 134443410132. Its totient is φ = 134443410130.

The previous prime is 134443410109. The next prime is 134443410137. The reversal of 134443410131 is 131014344431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134443410131 - 218 = 134443147987 is a prime.

It is a super-2 number, since 2×1344434101312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134443410094 and 134443410103.

It is not a weakly prime, because it can be changed into another prime (134443410137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67221705065 + 67221705066.

It is an arithmetic number, because the mean of its divisors is an integer number (67221705066).

Almost surely, 2134443410131 is an apocalyptic number.

134443410131 is a deficient number, since it is larger than the sum of its proper divisors (1).

134443410131 is an equidigital number, since it uses as much as digits as its factorization.

134443410131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 134443410131 its reverse (131014344431), we get a palindrome (265457754562).

The spelling of 134443410131 in words is "one hundred thirty-four billion, four hundred forty-three million, four hundred ten thousand, one hundred thirty-one".