Base | Representation |
---|---|
bin | 111110100110101110… |
… | …0111010001011010011 |
3 | 110212000120222212102102 |
4 | 1331031130322023103 |
5 | 4200320003111011 |
6 | 141432404511015 |
7 | 12466430062562 |
oct | 1751534721323 |
9 | 425016885372 |
10 | 134443410131 |
11 | 52020888a08 |
12 | 220809ab46b |
13 | c8a76265b4 |
14 | 6715683bd9 |
15 | 376cec473b |
hex | 1f4d73a2d3 |
134443410131 has 2 divisors, whose sum is σ = 134443410132. Its totient is φ = 134443410130.
The previous prime is 134443410109. The next prime is 134443410137. The reversal of 134443410131 is 131014344431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134443410131 - 218 = 134443147987 is a prime.
It is a super-2 number, since 2×1344434101312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134443410094 and 134443410103.
It is not a weakly prime, because it can be changed into another prime (134443410137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67221705065 + 67221705066.
It is an arithmetic number, because the mean of its divisors is an integer number (67221705066).
Almost surely, 2134443410131 is an apocalyptic number.
134443410131 is a deficient number, since it is larger than the sum of its proper divisors (1).
134443410131 is an equidigital number, since it uses as much as digits as its factorization.
134443410131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 134443410131 its reverse (131014344431), we get a palindrome (265457754562).
The spelling of 134443410131 in words is "one hundred thirty-four billion, four hundred forty-three million, four hundred ten thousand, one hundred thirty-one".
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