134443410137 has 2 divisors, whose sum is σ = 134443410138. Its totient is φ = 134443410136.

The previous prime is 134443410131. The next prime is 134443410139. The reversal of 134443410137 is 731014344431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134409491161 + 33918976 = 366619^2 + 5824^2 .

It is a cyclic number.

It is not a de Polignac number, because 134443410137 - 2¹⁴ = 134443393753 is a prime.

Together with 134443410139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 134443410097 and 134443410106.

It is not a weakly prime, because it can be changed into another prime (134443410131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67221705068 + 67221705069.

It is an arithmetic number, because the mean of its divisors is an integer number (67221705069).

Almost surely, 2^134443410137 is an apocalyptic number.

It is an amenable number.

134443410137 is a deficient number, since it is larger than the sum of its proper divisors (1).

134443410137 is an equidigital number, since it uses as much as digits as its factorization.

134443410137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 35.

Adding to 134443410137 its reverse (731014344431), we get a palindrome (865457754568).

The spelling of 134443410137 in words is "one hundred thirty-four billion, four hundred forty-three million, four hundred ten thousand, one hundred thirty-seven".