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13444401531000 = 23353112334751047
BaseRepresentation
bin1100001110100100010011…
…0001110000100001111000
31202121021100110101101012110
43003221010301300201320
53230233113242443000
644332134531412320
72555216542316166
oct303510461604170
952537313341173
1013444401531000
114313814195560
121611746a540a0
13766a56226b0b
143469d918c236
15184abe1a4850
hexc3a44c70878

13444401531000 has 512 divisors, whose sum is σ = 47887957278720. Its totient is φ = 3108497216000.

The previous prime is 13444401530999. The next prime is 13444401531131. The reversal of 13444401531000 is 13510444431.

It is a super-4 number, since 4×134444015310004 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 263347477 + ... + 263398523.

It is an arithmetic number, because the mean of its divisors is an integer number (93531166560).

Almost surely, 213444401531000 is an apocalyptic number.

13444401531000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13444401531000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23943978639360).

13444401531000 is an abundant number, since it is smaller than the sum of its proper divisors (34443555747720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13444401531000 is a wasteful number, since it uses less digits than its factorization.

13444401531000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51452 (or 51438 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 13444401531000 its reverse (13510444431), we get a palindrome (13457911975431).

The spelling of 13444401531000 in words is "thirteen trillion, four hundred forty-four billion, four hundred one million, five hundred thirty-one thousand".