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1344443234339 is a prime number
BaseRepresentation
bin10011100100000111000…
…011111011100000100011
311202112020120010200101102
4103210013003323200203
5134011404431444324
62505343444225015
7166063361636222
oct23440703734043
94675216120342
101344443234339
114791a2179a27
1219868b39b16b
1399a1b86973a
14490ddcc6cb9
1524e8aa35dae
hex139070fb823

1344443234339 has 2 divisors, whose sum is σ = 1344443234340. Its totient is φ = 1344443234338.

The previous prime is 1344443234327. The next prime is 1344443234357. The reversal of 1344443234339 is 9334323444431.

It is a weak prime.

It is an emirp because it is prime and its reverse (9334323444431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1344443234339 - 220 = 1344442185763 is a prime.

It is a super-2 number, since 2×13444432343392 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1344443234293 and 1344443234302.

It is not a weakly prime, because it can be changed into another prime (1344443234039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672221617169 + 672221617170.

It is an arithmetic number, because the mean of its divisors is an integer number (672221617170).

Almost surely, 21344443234339 is an apocalyptic number.

1344443234339 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344443234339 is an equidigital number, since it uses as much as digits as its factorization.

1344443234339 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4478976, while the sum is 47.

The spelling of 1344443234339 in words is "one trillion, three hundred forty-four billion, four hundred forty-three million, two hundred thirty-four thousand, three hundred thirty-nine".