Base | Representation |
---|---|
bin | 11001000010101101… |
… | …01101010111011001 |
3 | 1021200222012111221121 |
4 | 30201112231113121 |
5 | 210013243044001 |
6 | 10102030205241 |
7 | 654111250516 |
oct | 144126552731 |
9 | 37628174847 |
10 | 13444503001 |
11 | 577a087106 |
12 | 2732653821 |
13 | 13634c5627 |
14 | 9177d630d |
15 | 53a4a66a1 |
hex | 3215ad5d9 |
13444503001 has 2 divisors, whose sum is σ = 13444503002. Its totient is φ = 13444503000.
The previous prime is 13444502969. The next prime is 13444503019. The reversal of 13444503001 is 10030544431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10232334025 + 3212168976 = 101155^2 + 56676^2 .
It is an emirp because it is prime and its reverse (10030544431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13444503001 - 25 = 13444502969 is a prime.
It is not a weakly prime, because it can be changed into another prime (13444503031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722251500 + 6722251501.
It is an arithmetic number, because the mean of its divisors is an integer number (6722251501).
Almost surely, 213444503001 is an apocalyptic number.
It is an amenable number.
13444503001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13444503001 is an equidigital number, since it uses as much as digits as its factorization.
13444503001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
The spelling of 13444503001 in words is "thirteen billion, four hundred forty-four million, five hundred three thousand, one".
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