Base | Representation |
---|---|
bin | 10011100100000111101… |
… | …011100110001110101011 |
3 | 11202112021021200222120202 |
4 | 103210013223212032223 |
5 | 134011420112223224 |
6 | 2505344455142415 |
7 | 166063546215644 |
oct | 23440753461653 |
9 | 4675237628522 |
10 | 1344453632939 |
11 | 4791a803160a |
12 | 198692974a0b |
13 | 99a20a6a861 |
14 | 491014326cb |
15 | 24e8b8dbeae |
hex | 13907ae63ab |
1344453632939 has 2 divisors, whose sum is σ = 1344453632940. Its totient is φ = 1344453632938.
The previous prime is 1344453632909. The next prime is 1344453632941. The reversal of 1344453632939 is 9392363544431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1344453632939 - 216 = 1344453567403 is a prime.
It is a super-2 number, since 2×13444536329392 (a number of 25 digits) contains 22 as substring.
Together with 1344453632941, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1344453632909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672226816469 + 672226816470.
It is an arithmetic number, because the mean of its divisors is an integer number (672226816470).
Almost surely, 21344453632939 is an apocalyptic number.
1344453632939 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344453632939 is an equidigital number, since it uses as much as digits as its factorization.
1344453632939 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25194240, while the sum is 56.
The spelling of 1344453632939 in words is "one trillion, three hundred forty-four billion, four hundred fifty-three million, six hundred thirty-two thousand, nine hundred thirty-nine".
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