Base | Representation |
---|---|
bin | 10011100100001100011… |
… | …111011010010011000101 |
3 | 11202112110220112112111011 |
4 | 103210030133122103011 |
5 | 134012101241340141 |
6 | 2505400500442221 |
7 | 166065546122041 |
oct | 23441437322305 |
9 | 4675426475434 |
10 | 1344534324421 |
11 | 479239635292 |
12 | 1986b59a9371 |
13 | 99a346b08b2 |
14 | 4910c039021 |
15 | 24e93a2a881 |
hex | 1390c7da4c5 |
1344534324421 has 2 divisors, whose sum is σ = 1344534324422. Its totient is φ = 1344534324420.
The previous prime is 1344534324403. The next prime is 1344534324437. The reversal of 1344534324421 is 1244234354431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1342784993796 + 1749330625 = 1158786^2 + 41825^2 .
It is a cyclic number.
It is not a de Polignac number, because 1344534324421 - 217 = 1344534193349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344534324121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672267162210 + 672267162211.
It is an arithmetic number, because the mean of its divisors is an integer number (672267162211).
Almost surely, 21344534324421 is an apocalyptic number.
It is an amenable number.
1344534324421 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344534324421 is an equidigital number, since it uses as much as digits as its factorization.
1344534324421 is an evil number, because the sum of its binary digits is even.
The product of its digits is 552960, while the sum is 40.
Adding to 1344534324421 its reverse (1244234354431), we get a palindrome (2588768678852).
The spelling of 1344534324421 in words is "one trillion, three hundred forty-four billion, five hundred thirty-four million, three hundred twenty-four thousand, four hundred twenty-one".
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