Base | Representation |
---|---|
bin | 11110100100100100010001… |
… | …010111011000001110000111 |
3 | 122122001200220100012000111021 |
4 | 132210210101113120032013 |
5 | 120110344242042324341 |
6 | 1153543232030052011 |
7 | 40214666320500055 |
oct | 3644442127301607 |
9 | 578050810160437 |
10 | 134454242542471 |
11 | 399287a6778195 |
12 | 130b617194a007 |
13 | 5a03c996b1517 |
14 | 252b89763d1d5 |
15 | 10826e3ec69d1 |
hex | 7a49115d8387 |
134454242542471 has 2 divisors, whose sum is σ = 134454242542472. Its totient is φ = 134454242542470.
The previous prime is 134454242542447. The next prime is 134454242542507. The reversal of 134454242542471 is 174245242454431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134454242542471 - 227 = 134454108324743 is a prime.
It is a super-3 number, since 3×1344542425424713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134454242543471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67227121271235 + 67227121271236.
It is an arithmetic number, because the mean of its divisors is an integer number (67227121271236).
Almost surely, 2134454242542471 is an apocalyptic number.
134454242542471 is a deficient number, since it is larger than the sum of its proper divisors (1).
134454242542471 is an equidigital number, since it uses as much as digits as its factorization.
134454242542471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17203200, while the sum is 52.
The spelling of 134454242542471 in words is "one hundred thirty-four trillion, four hundred fifty-four billion, two hundred forty-two million, five hundred forty-two thousand, four hundred seventy-one".
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