13445545004112 has 40 divisors (see below), whose sum is σ = 37406195718304. Its totient is φ = 4137090770304.

The previous prime is 13445545004069. The next prime is 13445545004131. The reversal of 13445545004112 is 21140054554431.

It is a super-3 number, since 3×13445545004112³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10773673258 + ... + 10773674505.

Almost surely, 2^{13445545004112} is an apocalyptic number.

13445545004112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13445545004112 is an abundant number, since it is smaller than the sum of its proper divisors (23960650714192).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13445545004112 is a wasteful number, since it uses less digits than its factorization.

13445545004112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21547347787 (or 21547347781 counting only the distinct ones).

The product of its (nonzero) digits is 192000, while the sum is 39.

Adding to 13445545004112 its reverse (21140054554431), we get a palindrome (34585599558543).

The spelling of 13445545004112 in words is "thirteen trillion, four hundred forty-five billion, five hundred forty-five million, four thousand, one hundred twelve".