Base | Representation |
---|---|
bin | 10011100100010001101… |
… | …011111110011110010111 |
3 | 11202112200222120201221112 |
4 | 103210101223332132113 |
5 | 134012241101120112 |
6 | 2505413253205235 |
7 | 166100655131066 |
oct | 23442153763627 |
9 | 4675628521845 |
10 | 1344621504407 |
11 | 47928386a965 |
12 | 19871b03081b |
13 | 99a4978609c |
14 | 491198501dd |
15 | 24e9b4eba22 |
hex | 13911afe797 |
1344621504407 has 2 divisors, whose sum is σ = 1344621504408. Its totient is φ = 1344621504406.
The previous prime is 1344621504389. The next prime is 1344621504481. The reversal of 1344621504407 is 7044051264431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1344621504407 - 210 = 1344621503383 is a prime.
It is a super-2 number, since 2×13446215044072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344621504487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672310752203 + 672310752204.
It is an arithmetic number, because the mean of its divisors is an integer number (672310752204).
Almost surely, 21344621504407 is an apocalyptic number.
1344621504407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344621504407 is an equidigital number, since it uses as much as digits as its factorization.
1344621504407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 322560, while the sum is 41.
Adding to 1344621504407 its reverse (7044051264431), we get a palindrome (8388672768838).
The spelling of 1344621504407 in words is "one trillion, three hundred forty-four billion, six hundred twenty-one million, five hundred four thousand, four hundred seven".
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