Base | Representation |
---|---|
bin | 111110100111100001… |
… | …1111101110000001101 |
3 | 110212002110211101200211 |
4 | 1331033003331300031 |
5 | 4200343412104423 |
6 | 141435211522421 |
7 | 12500205521116 |
oct | 1751703756015 |
9 | 425073741624 |
10 | 134470425613 |
11 | 52035060057 |
12 | 22089a59411 |
13 | c8b00c4ca4 |
14 | 67190b720d |
15 | 377055e10d |
hex | 1f4f0fdc0d |
134470425613 has 2 divisors, whose sum is σ = 134470425614. Its totient is φ = 134470425612.
The previous prime is 134470425601. The next prime is 134470425619. The reversal of 134470425613 is 316524074431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72806609929 + 61663815684 = 269827^2 + 248322^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134470425613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134470425619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67235212806 + 67235212807.
It is an arithmetic number, because the mean of its divisors is an integer number (67235212807).
Almost surely, 2134470425613 is an apocalyptic number.
It is an amenable number.
134470425613 is a deficient number, since it is larger than the sum of its proper divisors (1).
134470425613 is an equidigital number, since it uses as much as digits as its factorization.
134470425613 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 40.
The spelling of 134470425613 in words is "one hundred thirty-four billion, four hundred seventy million, four hundred twenty-five thousand, six hundred thirteen".
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