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13448997901 is a prime number
BaseRepresentation
bin11001000011001111…
…10110110000001101
31021201021122212210101
430201213312300031
5210020420413101
610102310411101
7654164411263
oct144147666015
937637585711
1013448997901
1157816771a9
122734060a91
13136440a531
14918246433
1553aa93401
hex3219f6c0d

13448997901 has 2 divisors, whose sum is σ = 13448997902. Its totient is φ = 13448997900.

The previous prime is 13448997853. The next prime is 13448997907. The reversal of 13448997901 is 10979984431.

13448997901 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13219020676 + 229977225 = 114974^2 + 15165^2 .

It is a cyclic number.

It is not a de Polignac number, because 13448997901 - 217 = 13448866829 is a prime.

It is a super-2 number, since 2×134489979012 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13448997907) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6724498950 + 6724498951.

It is an arithmetic number, because the mean of its divisors is an integer number (6724498951).

Almost surely, 213448997901 is an apocalyptic number.

It is an amenable number.

13448997901 is a deficient number, since it is larger than the sum of its proper divisors (1).

13448997901 is an equidigital number, since it uses as much as digits as its factorization.

13448997901 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1959552, while the sum is 55.

The spelling of 13448997901 in words is "thirteen billion, four hundred forty-eight million, nine hundred ninety-seven thousand, nine hundred one".