Base | Representation |
---|---|
bin | 1100001110111001001111… |
… | …1010010100101010001111 |
3 | 1202121210212022022200112222 |
4 | 3003232103322110222033 |
5 | 3230331122140043003 |
6 | 44334504503445555 |
7 | 2555506064612363 |
oct | 303562372245217 |
9 | 52553768280488 |
10 | 13450024143503 |
11 | 4316139a95552 |
12 | 1612855a568bb |
13 | 76744106a86c |
14 | 346dadc012a3 |
15 | 184cecae3c38 |
hex | c3b93e94a8f |
13450024143503 has 2 divisors, whose sum is σ = 13450024143504. Its totient is φ = 13450024143502.
The previous prime is 13450024143467. The next prime is 13450024143511. The reversal of 13450024143503 is 30534142005431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13450024143503 - 226 = 13449957034639 is a prime.
It is a super-2 number, since 2×134500241435032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13450024143553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6725012071751 + 6725012071752.
It is an arithmetic number, because the mean of its divisors is an integer number (6725012071752).
Almost surely, 213450024143503 is an apocalyptic number.
13450024143503 is a deficient number, since it is larger than the sum of its proper divisors (1).
13450024143503 is an equidigital number, since it uses as much as digits as its factorization.
13450024143503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 13450024143503 its reverse (30534142005431), we get a palindrome (43984166148934).
The spelling of 13450024143503 in words is "thirteen trillion, four hundred fifty billion, twenty-four million, one hundred forty-three thousand, five hundred three".
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