Base | Representation |
---|---|
bin | 11110100101001111100000… |
… | …001010000011101011111011 |
3 | 122122020010201100211211100111 |
4 | 132211033200022003223323 |
5 | 120112124323332412123 |
6 | 1154020430111445151 |
7 | 40221231531153145 |
oct | 3645174012035373 |
9 | 578203640754314 |
10 | 134500661607163 |
11 | 39946457063575 |
12 | 131031675267b7 |
13 | 5a084865b78c7 |
14 | 252dc1c543c95 |
15 | 1083a0e2c390d |
hex | 7a53e0283afb |
134500661607163 has 2 divisors, whose sum is σ = 134500661607164. Its totient is φ = 134500661607162.
The previous prime is 134500661607139. The next prime is 134500661607187. The reversal of 134500661607163 is 361706166005431.
It is a balanced prime because it is at equal distance from previous prime (134500661607139) and next prime (134500661607187).
It is a cyclic number.
It is not a de Polignac number, because 134500661607163 - 29 = 134500661606651 is a prime.
It is not a weakly prime, because it can be changed into another prime (134500661607563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67250330803581 + 67250330803582.
It is an arithmetic number, because the mean of its divisors is an integer number (67250330803582).
Almost surely, 2134500661607163 is an apocalyptic number.
134500661607163 is a deficient number, since it is larger than the sum of its proper divisors (1).
134500661607163 is an equidigital number, since it uses as much as digits as its factorization.
134500661607163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 134500661607163 in words is "one hundred thirty-four trillion, five hundred billion, six hundred sixty-one million, six hundred seven thousand, one hundred sixty-three".
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