Base | Representation |
---|---|
bin | 11110100101010000010100… |
… | …001100000101110011101011 |
3 | 122122020012222012110012011121 |
4 | 132211100110030011303223 |
5 | 120112133120321232441 |
6 | 1154021052454040111 |
7 | 40221262261122514 |
oct | 3645202414056353 |
9 | 578205865405147 |
10 | 134501534555371 |
11 | 39946864899475 |
12 | 1310336b949037 |
13 | 5a085953cc1c9 |
14 | 252dca245ba0b |
15 | 1083a60c59dd1 |
hex | 7a5414305ceb |
134501534555371 has 2 divisors, whose sum is σ = 134501534555372. Its totient is φ = 134501534555370.
The previous prime is 134501534555351. The next prime is 134501534555429. The reversal of 134501534555371 is 173555435105431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134501534555371 - 27 = 134501534555243 is a prime.
It is not a weakly prime, because it can be changed into another prime (134501534555351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67250767277685 + 67250767277686.
It is an arithmetic number, because the mean of its divisors is an integer number (67250767277686).
Almost surely, 2134501534555371 is an apocalyptic number.
134501534555371 is a deficient number, since it is larger than the sum of its proper divisors (1).
134501534555371 is an equidigital number, since it uses as much as digits as its factorization.
134501534555371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9450000, while the sum is 52.
The spelling of 134501534555371 in words is "one hundred thirty-four trillion, five hundred one billion, five hundred thirty-four million, five hundred fifty-five thousand, three hundred seventy-one".
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