Base | Representation |
---|---|
bin | 10011100100101010110… |
… | …101011011100010010101 |
3 | 11202120210101110220220221 |
4 | 103210222311123202111 |
5 | 134014122103210031 |
6 | 2505523204154341 |
7 | 166114300241521 |
oct | 23445265334225 |
9 | 4676711426827 |
10 | 1345043413141 |
11 | 47947aa3a16a |
12 | 1988183989b1 |
13 | 99ab5cc881c |
14 | 491598b8d81 |
15 | 24ec358ba11 |
hex | 1392ad5b895 |
1345043413141 has 32 divisors (see below), whose sum is σ = 1471308064128. Its totient is φ = 1224868085760.
The previous prime is 1345043413139. The next prime is 1345043413157. The reversal of 1345043413141 is 1413143405431.
It is a cyclic number.
It is not a de Polignac number, because 1345043413141 - 21 = 1345043413139 is a prime.
It is a super-2 number, since 2×13450434131412 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1345043413097 and 1345043413106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1345043413111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16313781 + ... + 16396021.
It is an arithmetic number, because the mean of its divisors is an integer number (45978377004).
Almost surely, 21345043413141 is an apocalyptic number.
It is an amenable number.
1345043413141 is a deficient number, since it is larger than the sum of its proper divisors (126264650987).
1345043413141 is a wasteful number, since it uses less digits than its factorization.
1345043413141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82581.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 1345043413141 its reverse (1413143405431), we get a palindrome (2758186818572).
The spelling of 1345043413141 in words is "one trillion, three hundred forty-five billion, forty-three million, four hundred thirteen thousand, one hundred forty-one".
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