Base | Representation |
---|---|
bin | 10011100100101111000… |
… | …010111100010001111111 |
3 | 11202120222022102100200101 |
4 | 103210233002330101333 |
5 | 134014243200021444 |
6 | 2505534210341531 |
7 | 166116115615636 |
oct | 23445702742177 |
9 | 4676868370611 |
10 | 1345114063999 |
11 | 479506905202 |
12 | 198837b8a8a7 |
13 | 99ac7834674 |
14 | 4916502a51d |
15 | 24ec98953d4 |
hex | 1392f0bc47f |
1345114063999 has 2 divisors, whose sum is σ = 1345114064000. Its totient is φ = 1345114063998.
The previous prime is 1345114063981. The next prime is 1345114064057. The reversal of 1345114063999 is 9993604115431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1345114063999 - 29 = 1345114063487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1345114063939) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672557031999 + 672557032000.
It is an arithmetic number, because the mean of its divisors is an integer number (672557032000).
Almost surely, 21345114063999 is an apocalyptic number.
1345114063999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1345114063999 is an equidigital number, since it uses as much as digits as its factorization.
1345114063999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3149280, while the sum is 55.
The spelling of 1345114063999 in words is "one trillion, three hundred forty-five billion, one hundred fourteen million, sixty-three thousand, nine hundred ninety-nine".
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