Base | Representation |
---|---|
bin | 11110100101011010011000… |
… | …010111010011111111000110 |
3 | 122122021020212101121111012110 |
4 | 132211122120113103333012 |
5 | 120112322234024233014 |
6 | 1154030041123401450 |
7 | 40222124142106014 |
oct | 3645323027237706 |
9 | 578236771544173 |
10 | 134512342024134 |
11 | 39950400385738 |
12 | 13105487223286 |
13 | 5a095c8485c39 |
14 | 25306099318b4 |
15 | 1083e94967d59 |
hex | 7a56985d3fc6 |
134512342024134 has 16 divisors (see below), whose sum is σ = 284849665463088. Its totient is φ = 42199950438912.
The previous prime is 134512342024133. The next prime is 134512342024171. The reversal of 134512342024134 is 431420243215431.
It is a junction number, because it is equal to n+sod(n) for n = 134512342024092 and 134512342024101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134512342024133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 659374225507 + ... + 659374225710.
It is an arithmetic number, because the mean of its divisors is an integer number (17803104091443).
Almost surely, 2134512342024134 is an apocalyptic number.
134512342024134 is an abundant number, since it is smaller than the sum of its proper divisors (150337323438954).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134512342024134 is a wasteful number, since it uses less digits than its factorization.
134512342024134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1318748451239.
The product of its (nonzero) digits is 276480, while the sum is 39.
Adding to 134512342024134 its reverse (431420243215431), we get a palindrome (565932585239565).
The spelling of 134512342024134 in words is "one hundred thirty-four trillion, five hundred twelve billion, three hundred forty-two million, twenty-four thousand, one hundred thirty-four".
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