Base | Representation |
---|---|
bin | 11001000011101000… |
… | …11111101001100111 |
3 | 1021201111220012201001 |
4 | 30201310133221213 |
5 | 210022242424033 |
6 | 10102505414131 |
7 | 654234521005 |
oct | 144164375147 |
9 | 37644805631 |
10 | 13452311143 |
11 | 578352a517 |
12 | 273519a347 |
13 | 1364cca62b |
14 | 918869a75 |
15 | 53aee9e7d |
hex | 321d1fa67 |
13452311143 has 2 divisors, whose sum is σ = 13452311144. Its totient is φ = 13452311142.
The previous prime is 13452311129. The next prime is 13452311161. The reversal of 13452311143 is 34111325431.
It is a weak prime.
It is an emirp because it is prime and its reverse (34111325431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13452311143 - 225 = 13418756711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13452341143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6726155571 + 6726155572.
It is an arithmetic number, because the mean of its divisors is an integer number (6726155572).
Almost surely, 213452311143 is an apocalyptic number.
13452311143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13452311143 is an equidigital number, since it uses as much as digits as its factorization.
13452311143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4320, while the sum is 28.
Adding to 13452311143 its reverse (34111325431), we get a palindrome (47563636574).
The spelling of 13452311143 in words is "thirteen billion, four hundred fifty-two million, three hundred eleven thousand, one hundred forty-three".
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