Base | Representation |
---|---|
bin | 11110100101100101100011… |
… | …101101000001100110100111 |
3 | 122122022101211210100211210101 |
4 | 132211211203231001212213 |
5 | 120113021323404103242 |
6 | 1154035344043204531 |
7 | 40223030431250143 |
oct | 3645454355014647 |
9 | 578271753324711 |
10 | 134524343425447 |
11 | 399554a9904118 |
12 | 13107876516747 |
13 | 5a0a78b9bb531 |
14 | 25310277d6223 |
15 | 10844483b39b7 |
hex | 7a5963b419a7 |
134524343425447 has 2 divisors, whose sum is σ = 134524343425448. Its totient is φ = 134524343425446.
The previous prime is 134524343425429. The next prime is 134524343425481. The reversal of 134524343425447 is 744524343425431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134524343425447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134524343495447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67262171712723 + 67262171712724.
It is an arithmetic number, because the mean of its divisors is an integer number (67262171712724).
Almost surely, 2134524343425447 is an apocalyptic number.
134524343425447 is a deficient number, since it is larger than the sum of its proper divisors (1).
134524343425447 is an equidigital number, since it uses as much as digits as its factorization.
134524343425447 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 77414400, while the sum is 55.
The spelling of 134524343425447 in words is "one hundred thirty-four trillion, five hundred twenty-four billion, three hundred forty-three million, four hundred twenty-five thousand, four hundred forty-seven".
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