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134524742537 is a prime number
BaseRepresentation
bin111110101001001001…
…1001010101110001001
3110212020021000222111202
41331102103022232021
54201001313230122
6141444432033545
712501435305363
oct1752223125611
9425207028452
10134524742537
115206278a179
12220a40928b5
13c8bb432293
1467223b5d33
1537751dce92
hex1f524cab89

134524742537 has 2 divisors, whose sum is σ = 134524742538. Its totient is φ = 134524742536.

The previous prime is 134524742509. The next prime is 134524742549. The reversal of 134524742537 is 735247425431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81523954576 + 53000787961 = 285524^2 + 230219^2 .

It is a cyclic number.

It is not a de Polignac number, because 134524742537 - 222 = 134520548233 is a prime.

It is a super-2 number, since 2×1345247425372 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134524742491 and 134524742500.

It is not a weakly prime, because it can be changed into another prime (134524742557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67262371268 + 67262371269.

It is an arithmetic number, because the mean of its divisors is an integer number (67262371269).

Almost surely, 2134524742537 is an apocalyptic number.

It is an amenable number.

134524742537 is a deficient number, since it is larger than the sum of its proper divisors (1).

134524742537 is an equidigital number, since it uses as much as digits as its factorization.

134524742537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2822400, while the sum is 47.

The spelling of 134524742537 in words is "one hundred thirty-four billion, five hundred twenty-four million, seven hundred forty-two thousand, five hundred thirty-seven".