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1345253554213 is a prime number
BaseRepresentation
bin10011100100110111010…
…111000011100000100101
311202121100000220012021121
4103210313113003200211
5134020034402213323
62510000112213541
7166122431353642
oct23446727034045
94677300805247
101345253554213
11479578619278
1219887683a2b1
1399b1a6c395a
144917977adc9
1524ed6c4aa5d
hex139375c3825

1345253554213 has 2 divisors, whose sum is σ = 1345253554214. Its totient is φ = 1345253554212.

The previous prime is 1345253554207. The next prime is 1345253554223. The reversal of 1345253554213 is 3124553525431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1294638903684 + 50614650529 = 1137822^2 + 224977^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1345253554213 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1345253554213.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1345253554223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672626777106 + 672626777107.

It is an arithmetic number, because the mean of its divisors is an integer number (672626777107).

Almost surely, 21345253554213 is an apocalyptic number.

It is an amenable number.

1345253554213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345253554213 is an equidigital number, since it uses as much as digits as its factorization.

1345253554213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1080000, while the sum is 43.

The spelling of 1345253554213 in words is "one trillion, three hundred forty-five billion, two hundred fifty-three million, five hundred fifty-four thousand, two hundred thirteen".