Base | Representation |
---|---|
bin | 11110100101100110101010… |
… | …001000100010100001000111 |
3 | 122122022111220010210020201111 |
4 | 132211212222020202201013 |
5 | 120113031233402341041 |
6 | 1154040101213305451 |
7 | 40223101626655105 |
oct | 3645465210424107 |
9 | 578274803706644 |
10 | 134525525043271 |
11 | 39955a558a507a |
12 | 13107b46195287 |
13 | 5a0a919747a8b |
14 | 25310da6dcc75 |
15 | 10844b6ebc981 |
hex | 7a59aa222847 |
134525525043271 has 2 divisors, whose sum is σ = 134525525043272. Its totient is φ = 134525525043270.
The previous prime is 134525525043263. The next prime is 134525525043317. The reversal of 134525525043271 is 172340525525431.
It is a weak prime.
It is an emirp because it is prime and its reverse (172340525525431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134525525043271 - 23 = 134525525043263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134525525443271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67262762521635 + 67262762521636.
It is an arithmetic number, because the mean of its divisors is an integer number (67262762521636).
Almost surely, 2134525525043271 is an apocalyptic number.
134525525043271 is a deficient number, since it is larger than the sum of its proper divisors (1).
134525525043271 is an equidigital number, since it uses as much as digits as its factorization.
134525525043271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040000, while the sum is 49.
The spelling of 134525525043271 in words is "one hundred thirty-four trillion, five hundred twenty-five billion, five hundred twenty-five million, forty-three thousand, two hundred seventy-one".
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