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134525525114317 is a prime number
BaseRepresentation
bin11110100101100110101010…
…001000110011110111001101
3122122022111220010220212011211
4132211212222020303313031
5120113031233412124232
61154040101215014421
740223101630402201
oct3645465210636715
9578274803825154
10134525525114317
1139955a55943497
1213107b4620a411
135a0a91977120c
1425310da71ab01
1510844b6ed3a47
hex7a59aa233dcd

134525525114317 has 2 divisors, whose sum is σ = 134525525114318. Its totient is φ = 134525525114316.

The previous prime is 134525525114287. The next prime is 134525525114359. The reversal of 134525525114317 is 713411525525431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127344138118596 + 7181386995721 = 11284686^2 + 2679811^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134525525114317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134525525112317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67262762557158 + 67262762557159.

It is an arithmetic number, because the mean of its divisors is an integer number (67262762557159).

Almost surely, 2134525525114317 is an apocalyptic number.

It is an amenable number.

134525525114317 is a deficient number, since it is larger than the sum of its proper divisors (1).

134525525114317 is an equidigital number, since it uses as much as digits as its factorization.

134525525114317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2520000, while the sum is 49.

It can be divided in two parts, 134525525114 and 317, that added together give a palindrome (134525525431).

The spelling of 134525525114317 in words is "one hundred thirty-four trillion, five hundred twenty-five billion, five hundred twenty-five million, one hundred fourteen thousand, three hundred seventeen".