Base | Representation |
---|---|
bin | 11001000011110010… |
… | …01001101101110111 |
3 | 1021201121012020102211 |
4 | 30201321021231313 |
5 | 210023101011043 |
6 | 10102551514251 |
7 | 654251064301 |
oct | 144171115567 |
9 | 37647166384 |
10 | 13453532023 |
11 | 5784193808 |
12 | 2735688987 |
13 | 1365337249 |
14 | 918aa6971 |
15 | 53b18ba9d |
hex | 321e49b77 |
13453532023 has 2 divisors, whose sum is σ = 13453532024. Its totient is φ = 13453532022.
The previous prime is 13453532011. The next prime is 13453532033. The reversal of 13453532023 is 32023535431.
It is a strong prime.
It is an emirp because it is prime and its reverse (32023535431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13453532023 - 217 = 13453400951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13453532003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6726766011 + 6726766012.
It is an arithmetic number, because the mean of its divisors is an integer number (6726766012).
Almost surely, 213453532023 is an apocalyptic number.
13453532023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13453532023 is an equidigital number, since it uses as much as digits as its factorization.
13453532023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 31.
The spelling of 13453532023 in words is "thirteen billion, four hundred fifty-three million, five hundred thirty-two thousand, twenty-three".
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