Base | Representation |
---|---|
bin | 11001000011110110… |
… | …10111111100000001 |
3 | 1021201122021211112022 |
4 | 30201323113330001 |
5 | 210023223131221 |
6 | 10103012211225 |
7 | 654256041536 |
oct | 144173277401 |
9 | 37648254468 |
10 | 13454114561 |
11 | 5784551448 |
12 | 2735909b15 |
13 | 13654ac444 |
14 | 918bb8d8d |
15 | 53b2544ab |
hex | 321ed7f01 |
13454114561 has 2 divisors, whose sum is σ = 13454114562. Its totient is φ = 13454114560.
The previous prime is 13454114539. The next prime is 13454114563. The reversal of 13454114561 is 16541145431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13446721600 + 7392961 = 115960^2 + 2719^2 .
It is an emirp because it is prime and its reverse (16541145431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13454114561 - 210 = 13454113537 is a prime.
Together with 13454114563, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13454114563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6727057280 + 6727057281.
It is an arithmetic number, because the mean of its divisors is an integer number (6727057281).
Almost surely, 213454114561 is an apocalyptic number.
It is an amenable number.
13454114561 is a deficient number, since it is larger than the sum of its proper divisors (1).
13454114561 is an equidigital number, since it uses as much as digits as its factorization.
13454114561 is an evil number, because the sum of its binary digits is even.
The product of its digits is 28800, while the sum is 35.
Adding to 13454114561 its reverse (16541145431), we get a palindrome (29995259992).
The spelling of 13454114561 in words is "thirteen billion, four hundred fifty-four million, one hundred fourteen thousand, five hundred sixty-one".
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