Base | Representation |
---|---|
bin | 11001000011111000… |
… | …00101011111111101 |
3 | 1021201122122022112011 |
4 | 30201330011133331 |
5 | 210023300114211 |
6 | 10103020211221 |
7 | 654260446606 |
oct | 144174053775 |
9 | 37648568464 |
10 | 13454301181 |
11 | 5784669682 |
12 | 2735999b11 |
13 | 1365546379 |
14 | 918c26dad |
15 | 53b28e921 |
hex | 321f057fd |
13454301181 has 2 divisors, whose sum is σ = 13454301182. Its totient is φ = 13454301180.
The previous prime is 13454301173. The next prime is 13454301199. The reversal of 13454301181 is 18110345431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9417732025 + 4036569156 = 97045^2 + 63534^2 .
It is a cyclic number.
It is not a de Polignac number, because 13454301181 - 23 = 13454301173 is a prime.
It is a super-2 number, since 2×134543011812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13454302181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6727150590 + 6727150591.
It is an arithmetic number, because the mean of its divisors is an integer number (6727150591).
Almost surely, 213454301181 is an apocalyptic number.
It is an amenable number.
13454301181 is a deficient number, since it is larger than the sum of its proper divisors (1).
13454301181 is an equidigital number, since it uses as much as digits as its factorization.
13454301181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
The spelling of 13454301181 in words is "thirteen billion, four hundred fifty-four million, three hundred one thousand, one hundred eighty-one".
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