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1345545433 is a prime number
BaseRepresentation
bin101000000110011…
…0110010011011001
310110202212210100001
41100030312103121
510223424423213
6341303413001
745225642661
oct12014662331
93422783301
101345545433
11630586221
12316754161
131859c393b
14ca9b91a1
157d1da1dd
hex503364d9

1345545433 has 2 divisors, whose sum is σ = 1345545434. Its totient is φ = 1345545432.

The previous prime is 1345545431. The next prime is 1345545463. The reversal of 1345545433 is 3345455431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 990486784 + 355058649 = 31472^2 + 18843^2 .

It is an emirp because it is prime and its reverse (3345455431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1345545433 - 21 = 1345545431 is a prime.

Together with 1345545431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1345545392 and 1345545401.

It is not a weakly prime, because it can be changed into another prime (1345545431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672772716 + 672772717.

It is an arithmetic number, because the mean of its divisors is an integer number (672772717).

Almost surely, 21345545433 is an apocalyptic number.

It is an amenable number.

1345545433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345545433 is an equidigital number, since it uses as much as digits as its factorization.

1345545433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216000, while the sum is 37.

The square root of 1345545433 is about 36681.6770745286. The cubic root of 1345545433 is about 1103.9924978596.

The spelling of 1345545433 in words is "one billion, three hundred forty-five million, five hundred forty-five thousand, four hundred thirty-three".