Base | Representation |
---|---|
bin | 111110101100001001… |
… | …0001100010100100001 |
3 | 110212111020222012222121 |
4 | 1331120102030110201 |
5 | 4201203014301431 |
6 | 141502420104241 |
7 | 12504064616251 |
oct | 1753022142441 |
9 | 425436865877 |
10 | 134625150241 |
11 | 52104429a4a |
12 | 22111835081 |
13 | c90618951a |
14 | 6731871961 |
15 | 377de23611 |
hex | 1f5848c521 |
134625150241 has 2 divisors, whose sum is σ = 134625150242. Its totient is φ = 134625150240.
The previous prime is 134625150203. The next prime is 134625150301. The reversal of 134625150241 is 142051526431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 117583153216 + 17041997025 = 342904^2 + 130545^2 .
It is a cyclic number.
It is not a de Polignac number, because 134625150241 - 27 = 134625150113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134625150197 and 134625150206.
It is not a weakly prime, because it can be changed into another prime (134625150641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67312575120 + 67312575121.
It is an arithmetic number, because the mean of its divisors is an integer number (67312575121).
Almost surely, 2134625150241 is an apocalyptic number.
It is an amenable number.
134625150241 is a deficient number, since it is larger than the sum of its proper divisors (1).
134625150241 is an equidigital number, since it uses as much as digits as its factorization.
134625150241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 134625150241 its reverse (142051526431), we get a palindrome (276676676672).
The spelling of 134625150241 in words is "one hundred thirty-four billion, six hundred twenty-five million, one hundred fifty thousand, two hundred forty-one".
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