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134641365493 is a prime number
BaseRepresentation
bin111110101100101000…
…0000011000111110101
3110212112101111001010111
41331121100003013311
54201221142143433
6141504155423021
712504352503115
oct1753120030765
9425471431114
10134641365493
11521125a4788
1222117154a71
13c90964604b
146733a93045
153780577dcd
hex1f594031f5

134641365493 has 2 divisors, whose sum is σ = 134641365494. Its totient is φ = 134641365492.

The previous prime is 134641365487. The next prime is 134641365577. The reversal of 134641365493 is 394563146431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94720526289 + 39920839204 = 307767^2 + 199802^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134641365493 is a prime.

It is a super-2 number, since 2×1346413654932 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134641365403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67320682746 + 67320682747.

It is an arithmetic number, because the mean of its divisors is an integer number (67320682747).

Almost surely, 2134641365493 is an apocalyptic number.

It is an amenable number.

134641365493 is a deficient number, since it is larger than the sum of its proper divisors (1).

134641365493 is an equidigital number, since it uses as much as digits as its factorization.

134641365493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2799360, while the sum is 49.

The spelling of 134641365493 in words is "one hundred thirty-four billion, six hundred forty-one million, three hundred sixty-five thousand, four hundred ninety-three".