Base | Representation |
---|---|
bin | 1100010000000100001010… |
… | …0000110010100101110111 |
3 | 1202200201202202022022201211 |
4 | 3010001002200302211313 |
5 | 3231143313113113333 |
6 | 44352032133302251 |
7 | 2560120314112162 |
oct | 304010240624567 |
9 | 52621682268654 |
10 | 13470133332343 |
11 | 4323719111786 |
12 | 1616728494987 |
13 | 7692c725557c |
14 | 347d5a7caad9 |
15 | 1855c822becd |
hex | c4042832977 |
13470133332343 has 2 divisors, whose sum is σ = 13470133332344. Its totient is φ = 13470133332342.
The previous prime is 13470133332307. The next prime is 13470133332361. The reversal of 13470133332343 is 34323333107431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13470133332343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13470133332296 and 13470133332305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13470133333343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6735066666171 + 6735066666172.
It is an arithmetic number, because the mean of its divisors is an integer number (6735066666172).
Almost surely, 213470133332343 is an apocalyptic number.
13470133332343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13470133332343 is an equidigital number, since it uses as much as digits as its factorization.
13470133332343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 489888, while the sum is 40.
Adding to 13470133332343 its reverse (34323333107431), we get a palindrome (47793466439774).
The spelling of 13470133332343 in words is "thirteen trillion, four hundred seventy billion, one hundred thirty-three million, three hundred thirty-two thousand, three hundred forty-three".
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