Base | Representation |
---|---|
bin | 1100010000000101001110… |
… | …1111100001100011000111 |
3 | 1202200202111220020212010012 |
4 | 3010001103233201203013 |
5 | 3231144411114013432 |
6 | 44352120541220435 |
7 | 2560130424160412 |
oct | 304012357414307 |
9 | 52622456225105 |
10 | 13470422407367 |
11 | 4323857304062 |
12 | 16167a926171b |
13 | 7693420c9793 |
14 | 347d86d58b79 |
15 | 1855e37cdcb2 |
hex | c4053be18c7 |
13470422407367 has 2 divisors, whose sum is σ = 13470422407368. Its totient is φ = 13470422407366.
The previous prime is 13470422407361. The next prime is 13470422407381. The reversal of 13470422407367 is 76370422407431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13470422407367 - 224 = 13470405630151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13470422407361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6735211203683 + 6735211203684.
It is an arithmetic number, because the mean of its divisors is an integer number (6735211203684).
Almost surely, 213470422407367 is an apocalyptic number.
13470422407367 is a deficient number, since it is larger than the sum of its proper divisors (1).
13470422407367 is an equidigital number, since it uses as much as digits as its factorization.
13470422407367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4741632, while the sum is 50.
The spelling of 13470422407367 in words is "thirteen trillion, four hundred seventy billion, four hundred twenty-two million, four hundred seven thousand, three hundred sixty-seven".
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