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134706756792983 is a prime number
BaseRepresentation
bin11110101000001111011100…
…011000110011001010010111
3122122221211200111022000220212
4132220033130120303022113
5120124013414214333413
61154255232454520035
740242146003300204
oct3650173430631227
9578854614260825
10134706756792983
1139a158a6459021
12131370a436601b
135a21a3c61bcbb
142539badd30cab
1510890728d3ca8
hex7a83dc633297

134706756792983 has 2 divisors, whose sum is σ = 134706756792984. Its totient is φ = 134706756792982.

The previous prime is 134706756792953. The next prime is 134706756792989. The reversal of 134706756792983 is 389297657607431.

It is a strong prime.

It is an emirp because it is prime and its reverse (389297657607431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134706756792983 - 234 = 134689576923799 is a prime.

It is a super-3 number, since 3×1347067567929833 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134706756792989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67353378396491 + 67353378396492.

It is an arithmetic number, because the mean of its divisors is an integer number (67353378396492).

It is a 1-persistent number, because it is pandigital, but 2⋅134706756792983 = 269413513585966 is not.

Almost surely, 2134706756792983 is an apocalyptic number.

134706756792983 is a deficient number, since it is larger than the sum of its proper divisors (1).

134706756792983 is an equidigital number, since it uses as much as digits as its factorization.

134706756792983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880541440, while the sum is 77.

The spelling of 134706756792983 in words is "one hundred thirty-four trillion, seven hundred six billion, seven hundred fifty-six million, seven hundred ninety-two thousand, nine hundred eighty-three".