Base | Representation |
---|---|
bin | 10011100110100110011… |
… | …010001001001000100000 |
3 | 11202210010212121111011222 |
4 | 103212212122021020200 |
5 | 134032343324302111 |
6 | 2510505024354212 |
7 | 166216543315232 |
oct | 23464632111040 |
9 | 4683125544158 |
10 | 1347116634656 |
11 | 47a344248181 |
12 | 1990b6775968 |
13 | 9a05669bb10 |
14 | 492b4d94252 |
15 | 250955b47db |
hex | 139a6689220 |
1347116634656 has 48 divisors (see below), whose sum is σ = 2866310796888. Its totient is φ = 619533465600.
The previous prime is 1347116634607. The next prime is 1347116634667. The reversal of 1347116634656 is 6564366117431.
It can be written as a sum of positive squares in 4 ways, for example, as 843612858256 + 503503776400 = 918484^2 + 709580^2 .
It is a super-3 number, since 3×13471166346563 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1347116634598 and 1347116634607.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5645135 + ... + 5878926.
Almost surely, 21347116634656 is an apocalyptic number.
1347116634656 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
1347116634656 is an abundant number, since it is smaller than the sum of its proper divisors (1519194162232).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1347116634656 is a wasteful number, since it uses less digits than its factorization.
1347116634656 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11524365 (or 11524357 counting only the distinct ones).
The product of its digits is 6531840, while the sum is 53.
The spelling of 1347116634656 in words is "one trillion, three hundred forty-seven billion, one hundred sixteen million, six hundred thirty-four thousand, six hundred fifty-six".
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