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1347240023 is a prime number
BaseRepresentation
bin101000001001101…
…0100000001010111
310110220001212212122
41100103110001113
510224343140043
6341404010155
745246231323
oct12023240127
93426055778
101347240023
11631533408
1231723095b
1318616805c
14cacda983
157d422368
hex504d4057

1347240023 has 2 divisors, whose sum is σ = 1347240024. Its totient is φ = 1347240022.

The previous prime is 1347239947. The next prime is 1347240031. The reversal of 1347240023 is 3200427431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1347240023 - 210 = 1347238999 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1347239974 and 1347240001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1347245023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 673620011 + 673620012.

It is an arithmetic number, because the mean of its divisors is an integer number (673620012).

Almost surely, 21347240023 is an apocalyptic number.

1347240023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1347240023 is an equidigital number, since it uses as much as digits as its factorization.

1347240023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 26.

The square root of 1347240023 is about 36704.7683959455. The cubic root of 1347240023 is about 1104.4557622423.

Adding to 1347240023 its reverse (3200427431), we get a palindrome (4547667454).

The spelling of 1347240023 in words is "one billion, three hundred forty-seven million, two hundred forty thousand, twenty-three".